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Jul 06, 2023
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Yann in 't Veld
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## Units of $\hbar = 1$, $k_B = 1$, $\epsilon_0 = 1/(4\pi)$
In units where the reduced Planck constant $
\h
bar = 1$, the Boltzmann constant in $k_B = 1$ and the vacuum permittivity $
\e
psilon_0 = 1/(4
\p
i)$
-
The electron charge squared is $e^2 = 14.399$ $Å
\t
ext{eV}$
-
The elementary electron mass is $m_e = 0.1314$ $Å^{-2}
\t
ext{eV}^{-1}$
-
The temperature (in Kelvin) is given by $T[K] = T[
\t
ext{eV}] / k_B[
\t
ext{eV}]$, where $k_B[
\t
ext{eV}] = 8.617333262
\t
imes 10^{-5}$ eV/K
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